Answer
The equation has no real solutions.
Work Step by Step
$4x^{2}+25=-75$
Subtracting $25$ from both sides, we get
$4x^{2}=-100$
Dividing by $4$ on both sides, we obtain
$x^{2}=-25$
Taking square root on both sides, we have
$x=\pm\sqrt {-25}$
As the square of a real number cannot be negative, there are no real solutions for the equation.