Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 9 - Solving Quadratic Equations - Chapter Review - Page 535: 19

Answer

$x\approx1.48$ and $x\approx-1.48$.

Work Step by Step

$19=30-5x^{2}$ Adding $5x^{2}-19$ to both sides of the equation, we have $19+5x^{2}-19=30-5x^{2}+5x^{2}-19$ Or $5x^{2}=11$ Dividing both sides by $5$, we get $x^{2}=\frac{11}{5}$ Taking square root on both sides, we obtain $x=\pm\sqrt {\frac{11}{5}}\approx\pm 1.48$. The solutions of the given equation are $x\approx1.48$ and $x\approx-1.48$.
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