Answer
Above
Work Step by Step
$$f(x)=-3x^2-4x+8$$
$$D=b^2-4ac=(-4)^2-4(-3)(8)=16+96=112$$
Since the discriminant is positive (two $x$-intercepts) and $a<0$, the vertex is above the $x$-axis.
Big Ideas Math - Algebra 1, A Common Core Curriculum
by Larson, Ron; Boswell, Laurie
Published by
Big Ideas Learning LLC
ISBN 10:
978-1-60840-838-2
ISBN 13:
978-1-60840-838-2
Chapter 9 - Solving Quadratic Equations - 9.5 - Solving Quadratic Equations Using the Quadratic Formula - Exercises - Page 523: 67
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