Answer
Above
Work Step by Step
$$y=6x^2-2x+4$$
$$D=b^2-4ac=(-2)^2-4(6)(4)=4-96=-92$$
Since the discriminant is negative (no $x$-intercepts) and $a>0$, the vertex is above $x$-axis.
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.