Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 9 - Solving Quadratic Equations - 9.5 - Solving Quadratic Equations Using the Quadratic Formula - Exercises - Page 523: 66

Answer

Below

Work Step by Step

$$y=-15x^2+10x-25$$ $$D=b^2-4ac=(10)^2-4(-15)(-25)=100-1500=-1400$$ Since the discriminant is negative (no $x$-intercepts) and $a<0$, the vertex is below the $x$-axis.
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