Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 9 - Solving Quadratic Equations - 9.1 - Properties of Radicals - Monitoring Progress - Page 484: 27

Answer

$36-16\sqrt{5}$.

Work Step by Step

The given expression is $=(2\sqrt{5}-4)^2$ Use formula $(a-b)^2=a^2-2ab+b^2$. We have $a=2\sqrt{5}$ and $b=4$. $=(2\sqrt{5})^2-2(2\sqrt{5})(4)+(4)^2$ Simplify. $=4\cdot 5-16\sqrt{5}+16$ $=20-16\sqrt{5}+16$ Add like terms. $=36-16\sqrt{5}$.
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