Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 9 - Solving Quadratic Equations - 9.1 - Properties of Radicals - Monitoring Progress - Page 484: 23

Answer

$13\sqrt{2}-\sqrt{6}$.

Work Step by Step

The given expression is $=3\sqrt{2}-\sqrt{6}+10\sqrt{2}$ Use commutative property of addition. $=3\sqrt{2}+10\sqrt{2}-\sqrt{6}$ Use distributive property. $=(3+10)\sqrt{2}-\sqrt{6}$ Add. $=13\sqrt{2}-\sqrt{6}$.
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