Answer
$x=\pm3$
Work Step by Step
The zeros of the function are the $x$-intercepts of this function. The $x$-intercepts can be found by equating the function expression to $0$ and solving for $x$:
$$f(x)=3x^2-27$$
$$3x^2-27=0$$
$$3x^2=27$$
$$x^2=9$$
$$x=\pm\sqrt{9}=\pm3$$