Answer
$x=\pm1$
Work Step by Step
The zeros of the function is the same $x$-intercepts of this function. The $x$-intercepts can be found by equating function expression to $0$ and solving for $x$:
$$y=x^2-1$$
$$x^2-1=0$$
$$x^2=1$$
$$x=\pm\sqrt1=\pm1$$