Answer
$x=\pm7$
Work Step by Step
The zeros of the function are the $x$-intercepts of this function. The $x$-intercepts can be found by equating the function expression to $0$ and solving for $x$:
$$f(x)=-x^2+49$$
$$-x^2+49=0$$
$$-x^2=-49$$
$$x^2=49$$
$$x=\pm\sqrt{49}=\pm7$$