Answer
$(z+9)(3z-1)$.
Work Step by Step
The given polynomial is
$=3z^2+26z-9$
Rewrite $26z$ as $27z-1z$.
$=3z^2+27z-1z-9$
Group the terms.
$=(3z^2+27z)+(-1z-9)$
Factor each group.
$=3z(z+9)-1(z+9)$
Factor out $(z+9)$.
$=(z+9)(3z-1)$
Hence, the factor of the polynomial is $(z+9)(3z-1)$.
