Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 7 - Polynomial Equations and Factoring - Chapter Review - Page 411: 22

Answer

$(b+10)(b+8)$.

Work Step by Step

The given polynomial is $=b^2+18b+80$ Rewrite $18b$ as $10b+8b$. $=b^2+10b+8b+80$ Group the terms. $=(b^2+10b)+(8b+80)$ Factor each group. $=b(b+10)+8(b+10)$ Factor out $(b+10)$. $=(b+10)(b+8)$ Hence, the factor of the polynomial is $(b+10)(b+8)$.
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