Answer
$(t+6)(3t-2)$.
Work Step by Step
The given polynomial is
$=3t^2+16t-12$
Rewrite $16t$ as $18t-2t$.
$=3t^2+18t-2t-12$
Group the terms.
$=(3t^2+18t)+(-2t-12)$
Factor each group.
$=3t(t+6)-2(t+6)$
Factor out $(t+6)$.
$=(t+6)(3t-2)$
Hence, the factor of the polynomial is $(t+6)(3t-2)$.
