Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 7 - Polynomial Equations and Factoring - Chapter Review - Page 410: 15

Answer

$p^2+8p+16$.

Work Step by Step

The given expression is $=(p+4)^2$ Use formula $(a+b)^2=a^2+2ab+b^2$. We have $a=p$ and $b=4$. $=(p)^2+2(p)(4)+(4)^2$ Simplify. $=p^2+8p+16$ Hence, the product is $p^2+8p+16$.
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