Answer
$-12y^3+7y^2+20y-7$.
Work Step by Step
The given expression is
$=(-3y+1)(4y^2-y-7)$
Distribute $(4y^2-y-7)$ to each term of $(-3y+1)$.
$=-3y(4y^2-y-7)+1(4y^2-y-7)$
Use distributive property.
$=-3y(4y^2)-3y(-y)-3y(-7)+1(4y^2)+1(-y)+1(-7)$
Multiply.
$=-12y^3+3y^2+21y+4y^2-y-7$
Combine like terms.
$=-12y^3+7y^2+20y-7$
Hence, the product is $-12y^3+7y^2+20y-7$.
