Answer
$4y^2-16$.
Work Step by Step
The given expression is
$=(2y+4)(2y-4)$
Use sum and difference pattern $(a+b)(a-b)=a^2-b^2$.
We have $a=2y$ and $b=4$.
$=(2y)^2-4^2$
Simplify.
$=4y^2-16$
Hence, the product is $4y^2-16$.
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.