Answer
$n^2-10n+24$.
Work Step by Step
The given expression is
$=(n-6)(n-4)$
Distribute $(n-4)$ to each term of $(n-6)$.
$=n(n-4)-6(n-4)$
Use distributive property.
$=n(n)+n(-4)-6(n)-6(-4)$
Multiply.
$=n^2-4n-6n+24$
Combine like terms.
$=n^2-10n+24$
Hence, the product is $n^2-10n+24$.
