Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 6 - Exponential Functions and Sequences - 6.5 - Solving Exponential Equations - Exercises - Page 330: 56

Answer

$x=\frac{4}{7}$

Work Step by Step

$12^{2x-1}=(\sqrt[4] {12})^{x}$ This can be written as $12^{2x-1}=(12^{1/4})^{x}$ Using the property $(a^{m})^{n}=a^{mn}$, we get $12^{2x-1}=12^{\frac{x}{4}}$ Equating the exponents, we have $2x-1=\frac{x}{4}$ Multiply both sides by $4$ to get $4(2x-1)=x$ $\implies 8x-4=x$ Subtracting $x$ from both sides, we have $7x-4=0$ Adding $4$ to both sides, we obtain $7x=4$ Divide by $7$ on both sides to have $x=\frac{4}{7}$
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