Answer
$x=1$
Work Step by Step
$2(4^{2x+1})=128$
$\implies 4^{2x+1}=\frac{128}{2}=64$
$\implies 4^{2x+1}=4^{3}$
For the above equality to hold, the exponents must be equal.
$\implies 2x+1=3$
$\implies 2x=3-1=2$
$\implies x=\frac{2}{2}=1$