Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 6 - Exponential Functions and Sequences - 6.5 - Solving Exponential Equations - Exercises - Page 329: 9

Answer

$x=-5$

Work Step by Step

The given equation is $\Rightarrow 7^{x-5}=49^{x}$ Rewrite $49$ as $7^2$. $\Rightarrow 7^{x-5}=(7^2)^{x}$ Use $(a^n)^m=a^{n\cdot m}$ $\Rightarrow 7^{x-5}=7^{2x}$ Equate the exponents. $\Rightarrow x-5=2x$ Subtract $x$ from each side. $\Rightarrow x-5-x=2x-x$ Simplify. $\Rightarrow -5=x$ Check: $(x=-5)$ $\Rightarrow 7^{-5-5}=49^{-5}$ $\Rightarrow 7^{-10}=\frac{1}{49^{5}}$ $\Rightarrow \frac{1}{7^{10}}=\frac{1}{49^{5}}$ $\Rightarrow \frac{1}{282475249}=\frac{1}{282475249}$ True. Hence, the solution is $x=-5$.
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