Answer
$\frac{32x^{7}}{y^{6}}$
Work Step by Step
The given expression is
$=\frac{2^2y^{-6}}{8^{-1}z^0x^{-7}}$
Use $a^0=1$.
$=\frac{2^2y^{-6}}{8^{-1}(1)x^{-7}}$
Use $a^{-n}=\frac{1}{a^n}$.
$=\frac{2^28^{1}x^{7}}{y^{6}}$
Use $2^2=4$.
$=\frac{4\cdot8^{1}x^{7}}{y^{6}}$
Simplify.
$=\frac{32x^{7}}{y^{6}}$.