Answer
$\frac{49q^{9}}{p^{8}}$
Work Step by Step
The given expression is
$=\frac{p^{-8}}{7^{-2}q^{-9}}$
Use $a^{-n}=\frac{1}{a^n}$.
$=\frac{7^{2}q^{9}}{p^{8}}$
Use $7^2=49$.
$=\frac{49q^{9}}{p^{8}}$.
Big Ideas Math - Algebra 1, A Common Core Curriculum
by Larson, Ron; Boswell, Laurie
Published by
Big Ideas Learning LLC
ISBN 10:
978-1-60840-838-2
ISBN 13:
978-1-60840-838-2
Chapter 6 - Exponential Functions and Sequences - 6.1 - Properties of Exponents - Exercises - Page 296: 20
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