Answer
$\frac{b^{7}}{64}$
Work Step by Step
The given expression is
$=\frac{4^{-3}a^0}{b^{-7}}$
Use $a^0=1$.
$=\frac{4^{-3}(1)}{b^{-7}}$
Use $a^{-n}=\frac{1}{a^n}$.
$=\frac{b^{7}}{4^{3}}$
Use $4^3=64$.
$=\frac{b^{7}}{64}$.
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