Chapter 10 - Radical Functions and Equations - 10.4 - Inverse of a Function - Exercises - Page 572: 12

$x=\frac{3y-12}{2}$ When output $y=2$, input $x=-3$

$y=\frac{2}{3}x+4$ Subtracting $4$ from both sides, we obtain $y-4=\frac{2}{3}x$ Now, multiply both sides by $\frac{3}{2}$ to get $\frac{3}{2}(y-4)=x$ Or $x=\frac{3y-12}{2}$ When output $y=2$, Input $x=\frac{3(2)-12}{2}=-3$