Chapter 10 - Radical Functions and Equations - 10.4 - Inverse of a Function - Exercises - Page 572: 10

$x=\frac{1}{2}(y+3)$ When output $y=2$, Input $x=\frac{5}{2}$

$y=2x-3$ Add $3$ on both sides of the equation to get $y+3=2x-3+3$ $\implies y+3=2x$ Now, divide both sides by $2$. Then, $\frac{y+3}{2}=x$ Or $x=\frac{1}{2}(y+3)$ When output $y=2$, Input $x=\frac{1}{2}(2+3)=\frac{5}{2}$