Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 10 - Radical Functions and Equations - 10.3 - Solving Radical Equations - Monitoring Progress - Page 561: 8

Answer

$n=\frac{1}{4}$

Work Step by Step

The given equation is $\Rightarrow \sqrt{n}=\sqrt{5n-1}$ Square each side of the equation. $\Rightarrow (\sqrt{n})^2=(\sqrt{5n-1})^2$ Simplify. $\Rightarrow n=5n-1$ Add $1-n$ to each side. $\Rightarrow n+1-n=5n-1+1-n$ Simplify. $\Rightarrow 1=4n$ Divide each side by $4$. $\Rightarrow \frac{1}{4}=\frac{4n}{4}$ Simplify. $\Rightarrow \frac{1}{4}=n$ Check $n=\frac{1}{4}$. $\Rightarrow \sqrt{n}=\sqrt{5n-1}$ $\Rightarrow \sqrt{\frac{1}{4}}=\sqrt{5(\frac{1}{4})-1}$ $\Rightarrow \sqrt{\frac{1}{4}}=\sqrt{\frac{5}{4}-1}$ $\Rightarrow \sqrt{\frac{1}{4}}=\sqrt{\frac{5-4}{4}}$ $\Rightarrow \sqrt{\frac{1}{4}}=\sqrt{\frac{1}{4}}$ True. Hence, the solution is $n=\frac{1}{4}$.
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