Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 10 - Radical Functions and Equations - 10.3 - Solving Radical Equations - Monitoring Progress - Page 561: 7

Answer

$x=8$

Work Step by Step

The given equation is $\Rightarrow \sqrt{3x+1}=\sqrt{4x-7}$ Square each side of the equation. $\Rightarrow (\sqrt{3x+1})^2=(\sqrt{4x-7})^2$ Simplify. $\Rightarrow 3x+1=4x-7$ Add $7-3x$ to each side. $\Rightarrow 3x+1+7-3x=4x-7+7-3x$ Simplify. $\Rightarrow 8=x$ Check $x=8$. $\Rightarrow \sqrt{3x+1}=\sqrt{4x-7}$ $\Rightarrow \sqrt{3(8)+1}=\sqrt{4(8)-7}$ $\Rightarrow \sqrt{24+1}=\sqrt{32-7}$ $\Rightarrow \sqrt{25}=\sqrt{25}$ True. Hence, the solution is $x=8$.
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