Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 10 - Radical Functions and Equations - 10.3 - Solving Radical Equations - Monitoring Progress - Page 561: 6

Answer

$w=30$

Work Step by Step

The given equation is $\Rightarrow 15=6+\sqrt{3w-9}$ Subtract $6$ from each side. $\Rightarrow 15-6=6+\sqrt{3w-9}-6$ Simplify. $\Rightarrow 9=\sqrt{3w-9}$ Square each side of the equation. $\Rightarrow 9^2=(\sqrt{3w-9})^2$ Simplify. $\Rightarrow 81=3w-9$ Add $9$ to each side. $\Rightarrow 81+9=3w-9+9$ Simplify. $\Rightarrow 90=3w$ Divide each side by $3$. $\Rightarrow \frac{90}{3}=\frac{3w}{3}$ Simplify. $\Rightarrow 30=w$ Check $w=30$. $\Rightarrow 15=6+\sqrt{3w-9}$ $\Rightarrow 15=6+\sqrt{3(30)-9}$ $\Rightarrow 15=6+\sqrt{90-9}$ $\Rightarrow 15=6+\sqrt{81}$ $\Rightarrow 15=6+9$ $\Rightarrow 15=15$ True. Hence, the solution is $w=30$.
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