Answer
$x=0,-2, +2$ and $y=8$
Work Step by Step
We have: $2x^2 =x^4 -2x^2$
Re-write as: $x^4 -2x^2-2x^2=0$
$\implies x^2 (x^2-4)=0$
We get: $x^2 (x-2)(x+2)=0$
Thus, $x=0,-2, +2$
We will plug the value of $x$ into the expression of $y$ to find the value of $y$.
So, $y=2(2)^2=8$
Therefore, $x=0,-2, +2$ and $y=8$
