Answer
$x=5;y=4$
Work Step by Step
Plug the value of $x$ into the first equation.
$(1+y)^2-y^2=9 \implies 1+2y=9$
We get: $y=4$
We will plug the value of $y$ back into the expression of $x$ to find the value of $x$.
$x-4 =1 \implies x=5$
Thus, $x=5;y=4$
