Answer
$x=-1;y=\dfrac{-2}{3}$
Work Step by Step
We need to isolate $x$ in the second equation.
$x=-9y-7$
Now, plug the value of $x$ into the first equation.
$10(-9y-7)+6y+14=0 \implies -84y-56=0$
We get: $y=-\dfrac{2}{3}$
We will plug the value of $y$ into the expression of $x$ to find the value of $x$.
$x=-9(-\dfrac{2}{3})-7=0=-1$
Thus, $x=-1;y=\dfrac{-2}{3}$
