Answer
$(\frac{90}{31},\frac{-67}{31})$
Work Step by Step
Multiplying equation 1 by $200$ and equation 2 by $300$, we get:
$10x-6y=42$ and $21x+6y=48$.
Adding both equations, we get $31x=90$ and thus $x=\frac{90}{31}$ (Elimination)
Substituting the value of x in equation 1: $10\times\frac{90}{31}-6y=42$
This becomes $6y=\frac{900}{31}-42$ and $y=(900−1302)/186=\frac{-67}{31}$
Thus, we get $(\frac{90}{31},\frac{-67}{31})$ as a solution.
