Chapter 9 - 9.2 - Two-Variable Linear Systems - 9.2 Exercises - Page 646: 14

$(6,2)$

Given that $3x-5y=8$ and $2x+5y=22$ Adding both equations, we get $5x=30$ and thus $x=6$ (Elimination) Substituting the value of x in equation 2: $12+5y=22$ This becomes $5y=10$ and $y=2$ Thus, we get $(6,2)$ as a solution.