Chapter 9 - 9.2 - Two-Variable Linear Systems - 9.2 Exercises - Page 646: 10

$No$ $Solution$

Given that $3x+2y=3$ and $6x+4y=14$ The first equation becomes: $-2(3x+2y)=-2(3)$ (Multiplying both sides by -2) Thus, $-6x-4y=-6$ Adding both equations, $0=8$, which is false (Elimination) Thus, no solution.