Answer
$cos~6θ+cos~5θ=2~cos\frac{11θ}{2}~cos\frac{θ}{2}$
Work Step by Step
$cos~6θ+cos~5θ=2~cos(\frac{6θ+5θ}{2})~cos(\frac{6θ-5θ}{2})=2~cos\frac{11θ}{2}~cos\frac{θ}{2}$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 7 - Review Exercises - Page 553: 77
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