Answer
The identity is verified.
$tan(\pi-x)=-tan~x$
Work Step by Step
$tan(\pi-x)=\frac{tan~\pi-tan~x}{1+tan~\pi·tan~x}=\frac{0-tan~x}{1+(0)·tan~x}=\frac{-tan~x}{1}=-tan~x$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 7 - Review Exercises - Page 553: 59
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