Answer
$2~sin~7θ~cos~3θ=sin~10θ+sin~4θ$
Work Step by Step
$2~sin~7θ~cos~3θ=2(\frac{1}{2})[sin(7θ+3θ)+sin(7θ-3θ)]=sin~10θ+sin~4θ$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 7 - Review Exercises - Page 553: 76
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