Chapter 6 - 6.7 - Applications and Models - 6.7 Exercises - Page 494: 7

$A=17.2°$ $B=72.8°$ $C=90°$ $a=4.4$ $b=14.21$ $c=14.88$

$A+B+C=180°$ $A+72.8°+90°=180°$ $A=180°-72.8°-90°=17.2°$ $tan~A=\frac{opp}{adj}$ $tan~17.2°=\frac{4.4}{b}$ $b=\frac{4.4}{tan~17.2°}=14.21$ $sin~A=\frac{opp}{hyp}$ $sin~17.2°=\frac{4.4}{c}$ $c=\frac{4.4}{sin~17.2°}=14.88$