Answer
$$ h=2.83$$
Work Step by Step
For an isosceles triangle, given the base angle, $\theta$, we know that the height is:
$$h=.5btan\theta \\ h =.5(14)tan(22^{\circ})\\ h=2.83$$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 6 - 6.7 - Applications and Models - 6.7 Exercises - Page 494: 14
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