Answer
$sin[arcsin(-0.2)]=-0.2$
Work Step by Step
$-0.2$ does lie in the range of $sin~x$: ($-1\leq x\leq1$). So,
$sin[arcsin(-0.2)]=-0.2$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 6 - 6.6 - Inverse Trigonometric Functions - 6.6 Exercises - Page 484: 48
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