Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 6 - 6.6 - Inverse Trigonometric Functions - 6.6 Exercises - Page 484: 16

Answer

45 degrees

Work Step by Step

The $arcsin(.5\sqrt2)$ is the angle whose sine is $.5\sqrt2$. Thus, we see that the expression evaluates to: $$45\ degrees$$
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