Answer
It is not possible.
Work Step by Step
$-\sqrt 3$ does not lie in the range of $cos~x$: ($-1\leq x\leq1$). So,
$cos[arccos(-\sqrt 3)]$ does not exist.
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 6 - 6.6 - Inverse Trigonometric Functions - 6.6 Exercises - Page 484: 47
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