Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 6 - 6.3 - Trigonometric Functions of Any Angle - 6.3 Exercises - Page 454: 97

Answer

($-\frac{1}{2}$,$-\frac{\sqrt 3}{2}$) cos($\frac{4\pi}{3}$) = $-\frac{1}{2}$ sin($\frac{4\pi}{3}$) = $-\frac{\sqrt 3}{2}$ tan($\frac{4\pi}{3}$) = $\sqrt 3$

Work Step by Step

Using the unit circle when t = $\frac{4\pi}{3}$, The (x,y) point is ($-\frac{1}{2}$,$-\frac{\sqrt 3}{2}$) Using the coordinate points: cos($\frac{4\pi}{3}$) = $-\frac{1}{2}$ sin($\frac{4\pi}{3}$) = $-\frac{\sqrt 3}{2}$ tan($\frac{4\pi}{3}$) = $\sqrt 3$
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