Answer
($-\frac{\sqrt 2}{2}$,$\frac{\sqrt 2}{2}$)
cos($\frac{3\pi}{4}$) = $-\frac{\sqrt 2}{2}$
sin($\frac{3\pi}{4}$) = $\frac{\sqrt 2}{2}$
tan($\frac{3\pi}{4}$) = -1
Work Step by Step
Using the unit circle when t = $\frac{3\pi}{4}$,
The (x,y) point is ($-\frac{\sqrt 2}{2}$,$\frac{\sqrt 2}{2}$)
Using the coordinate points:
cos($\frac{3\pi}{4}$) = $-\frac{\sqrt 2}{2}$
sin($\frac{3\pi}{4}$) = $\frac{\sqrt 2}{2}$
tan($\frac{3\pi}{4}$) = -1