Answer
($-\frac{\sqrt 3}{2}$,$\frac{1}{2}$)
cos($\frac{5\pi}{6}$) = $-\frac{\sqrt 3}{2}$
sin($\frac{5\pi}{6}$) = $\frac{1}{2}$
tan($\frac{5\pi}{6}$) = $-\frac{1}{\sqrt 3}$
Work Step by Step
Using the unit circle when t = $\frac{5\pi}{6}$.
The (x,y) point is ($-\frac{\sqrt 3}{2}$,$\frac{1}{2}$)
Using the coordinate points:
cos($\frac{5\pi}{6}$) = $-\frac{\sqrt 3}{2}$
sin($\frac{5\pi}{6}$) = $\frac{1}{2}$
tan($\frac{5\pi}{6}$) = $-\frac{1}{\sqrt 3}$
