Answer
$\log_a\frac{x}{y}=\log_ax-\log_ay$
True.
Work Step by Step
$a^{\log_a\frac{x}{y}}=a^{(\log_ax-\log_ay)}$
$\frac{x}{y}=\frac{a^{\log_ax}}{a^{\log_ay}}$
$\frac{x}{y}=\frac{x}{y}$
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