Answer
$\log_a(xy)=\log_ax+\log_ay$
True.
Use the inverse property.
Work Step by Step
$\log_a(xy)=\log_ax+\log_ay$
$a^{\log_a(xy)}=a^{\log_ax+\log_ay}$
$xy=(a^{\log_ax})(a^{\log_ay})$
$xy=(x)(y)$
$xy=xy$
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