Answer
$\log_a(x-y)=\log_ax-\log_ay$
False.
Work Step by Step
$\log_a(x-y)\ne \log_ax-\log_ay$
$a^{\log_a(x-y)}\ne a^{(\log_ax-\log_ay)}$
$x-y\ne \frac{a^{\log_ax}}{a^{\log_ay}}$
$x-y\ne\frac{x}{y}$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 5 - 5.4 - Exponential and Logarithmic Equations - 5.4 - Page 397: 91
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