Answer
$x=6$ and $y=0$
Work Step by Step
$\dfrac{5x+20}{x^2-2x-24}=\dfrac{5(x+4)}{(x+4)(x-6)}$
or, $x-6=0 \implies x=6$
Find the horizontal asymptotes. The degree of the numerator is equal to the degree of the denominator.
$y=0$
So, $x=6$ and $y=0$
