Answer
Domain: all real numbers except $x=4~~and~~x=6$
Work Step by Step
$\frac{8}{x^2-10x+24}$
The denominator must be different from $0$.
$x^2-10x+24\ne0$
$x^2-6x-4x+24\ne0$
$x(x-6)-4(x-6)\ne0$
$(x-4)(x-6)\ne0$
$x-4\ne0~~and~~x-6\ne0$
$x\ne4~~and~~x\ne6$
